another_jim wrote:If you are using a PID, the load will be constant (or cycling inside a 1 second window), so it may be necessary to look at heavier duty solutions than for an SSR that interposes a pstat.
As Ken says, the biggest stress on the SSR is heating the machine. Once the machine is heated, the same power is generated by PID or pstat as it's the heat loss that controls the heat input, ignoring minor differences due to temperature swing. If the SSR w heatsink can handle start-up, it can handle temperature maintenance, regardless of control method.
RayJohns wrote:The 100A SSR shows it has 22% lower cooling requirements in terms of what heatsink it need. Or, put another way, given the same conditions, the more expensive SSR would operate around 10C degrees cooler given the same heatsink (if I'm reading the chart correct).
The chart is not the temperature the device runs at for a given current, but the maximum current at an ambient temperature when mounted upon a heatsink with a given thermal resistance. The larger SSR has a bigger chunk of silicon mounted to a heavier base, so it can take more abuse. Electronic specs can be off by 25%, so if the heatsink is undersized / non-existent as in the case of Jim's Isomac, it's gonna fail. Ray is correct that the large device will run cooler and therefore should last longer. However, only by a factor of 2. Proper cooling will extend that several factors of 2 and precludes the possibility of crossing into the red zone.
From the 100A SSR data sheet :

The SSR dissipates ~16w. Without a heatsink, the junction temperature is Tj = Ta + P x °C/W. Say the datasheet is very conservative and the Rth_j-a is only 5 and the machine internal temperature a sultry 40°C : 40 + 16 * 5 = 120°C or very close to the maximum allowable junction temperature. A rule of thumb : the life of an electronic component is doubled for every 10°C drop in temperature, so keeping the device cool is paramount. Note that the Rth_j-a does not change with the increase in current capacity, but the Rth_j-c and Rth_c-s drop dramatically.
These number are only effective when connected to a heatsink. With a heatsink like the RHS300, the 25A SSR has a Tj of 40 + 16 * (5 + 0.8 + 0.2) = 136°C while the 100A has a Tj of 40 + 16 + * (5 + 0.3 + 0.1) = 126.4°C. Too hot in either case. Increase the machine temperature to a more likely 50 or 60°C and the device is in distress. $15 for a properly sized device + $10 for a heatsink ensuring optimal performance makes much more sense than spending $40 for an improperly cooled, grossly oversize device with marginal reliability.
Ken Fox wrote: I taped a bare TC next to the SSR baseplate where it affixes to the bottom of the case. On warm up, it never got more than a few degrees higher than ambient temp, eons below the heat level that would be concerning, which I found in an online chart for that particular SSR on the Mfr's website.
Measurement of this sort require specialized sensors to get accurate readings. The fact that the sheet metal is not warm maybe of concern. It could indicate a poor contact between the SSR base and the pan. Poor contact may be due to a dished pan, swarf, mounting holes not deburred, etc. A better test is to test the temperature of the pan between the mounting bolts on the outside of the machine
near the end of warm up.. The temperature should be quite high, indicating good heat transfer from the case, declining evenly with distance from the center.
Obviously the machine sheet metal can act as a heat sink. As long as the surface mates evenly with the SSR, is of sufficient mass and large enough temperature differential, it's fine. The thicker the material and the larger the surface area, the better. Stainless steel [k~16] is about 1/3 as effective as steel [k~50] which is about 1/4 as effective as aluminum [k~200] in dissipating heat.
Very rough calculation for a Vibiemme Domobar Super :
pan where SSR mounted .25m x .15m x .0015m
Stainless thermal conductivity ~16
Steady state thermal resistance about .0025 K/W
Horizontal surface thermal radiance efficiency to still air about .1%
Bottom surface efficiency derating 50%
.0025 / .001 / 0.5 = 5 K/W - Borderline.
A steel pan with the same dimensions would have a thermal resistance of about 1.7 K/W, but paint could decrease the heat transfer to the air. A very slight forced air current drastically reduces heat buildup, but a heatsink is dead quiet and never fails.