gscace wrote:Walter:
If you wanna use the ideal gas law, you have to have a closed system. You can then relate temperature and pressure as you know. But in order to do so, the number of moles of gas in the system has to remain constant, which is not the case in espresso machines.
Since liquid exists in an espresso machine boiler, the number of moles of water vapor in the gas phase varies. The amount of water in the vapor phase is a function of temperature only, with a weak interaction between the water vapor and the other constituents in the gas above the liquid. As far as the pressure contribution of other gasses is concerned, they would contribute to the total pressure based on the ideal gas law because the number of molecules is conserved in the system, unless they are forced out by some mechanism. Mechanisms that seem reasonable and likely to me are increase in pressure due to increasing temperature when the vacuum breaker is open and the system is heating up, and anytime the steam valve or hot water valve are opened after the machine is up to temperature. There is no air generator inside the boiler. But there's plenty of liquid water that will flash to vapor as soon as the pressure drops below the saturation vapor pressure, such as occurs when opening valves. So it's a very reasonable assumption that water is the predominant species in the vapor phase in the boiler, and therefore the pressure is pretty much due to water vapor pressure and nothing else.
I do not want to use the ideal gas law for an
exact description of the gaseous phase above the water in the boiler, and more to the point, I never claimed to (which I tried to make clear in my first post). But the ideal gas law serves well enough to describe the mutual dependencies of pressure and temperature. And exactly these dependencies are the reason why we can regulate the brewing temperature of our machines by regulating the boiler pressure.
And this, I believe, was the question raised in the first post of this thread. The question was answered well enough by cannonfodder, but since he mentioned a formula, I thought that was the one he meant.
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At this point we might as well end our little exchange, because the rest is pretty much off topic here, nonetheless I will share my thoughts with you:
While I agree with you, that the ideal gas law does not describe the system exactly, I still think it is a reasonable first level approach. At any given moment when your machine is idling, the boiling water is in perfect equilibrium with the gaseous phase above it. We have a closed system at a certain temperature with a certain pressure and a certain number of molecules in the gaseous phase. And with regard to the pressure it is IMO entirely irrelevant whether the gaseous molecules are N2, O2, CO2, H2o or whatever, they all behave very similar if not equally in that aspect.
Of course this equilibrium is disturbed as soon as you interrupt the system e.g. by opening the steam valve. Then our little quasi-static (notabene: it is not really static, but in equilibrium, thus a static description can describe it reasonably well) system becomes dynamic all of a sudden. And if we leave the steam valve open long enough our pressure drops - roughly - to the atmospheric value, our little pressure cooker has become an ordinary pot with boiling water in it, and the pressurestat is of little value to regulate the temperature there...
Most of your considerations above address the disturbed system, where no equilibrium exists and dynamic processes are predominant in the system. But there the description becomes rather complex...
gscace wrote:You mention Clausius / Clapeyron, which is the basis for the water vapor pressure correlations developed by various folks. Take a look at Arnold Wexler's vapor pressure formulation for water from 0 to 100C. That's what we use here, corrected to ITS-90. It does not look anything like the ideal gas law. And use of the ideal gas law does not get you anywhere close to the right answer. A simple check would be to attempt to calculate the difference in temperature with respect to pressure using the ideal gas law, and then to do it with the steam tables. They give very different answers.
-Greg
You certainly must be aware what the temperature range in the boiler is, but for those here who aren't, we should be fair enough to mention that the temperature is well beyond 100°C, thus I seriously doubt, that a
vapor pressure formulation for water from 0 to 100C - corrected by the Triple-point of water at 0°C does the trick of describing a closed, overheated, pressurized system exactly, whereas the Clausius-Clapeyron equations dont...
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P.S.: Edited as per request of moderator to tone down the rhetoric. And hereby i humbly bow out of this discussion